What is the amount of chlorine evoled when `2` amperes of current is passed for `30` minumtes in an aqueous solution of `NaCI` ?

Options

A. 66 g
B. 1.32 g
C. 33 g
D. 99 g

Answer

B

Explanation

At anode `, Cl^(-) to (1)/(2) Cl_(2) + e^(-)`
Equivalent wt. of chlorine `E_(Cl_(2)) = (35.5 xx 2)/(2) = 35.5`
`W_(Cl_(2)) = (E_(Cl_(2)) xx I xx t)/(96500) = (35.5 x 2 xx 30 xx 60)/(96500) = 1.32` g