A 100.0mL dilute solution of `Ag^(+)` is electrolysed for 15.0 minutes with a current of 1.25mA and the silver is removed completely. What was the initial`[Ag^=]`?

Options

A. `2.32 xx 10^(-1)`
B. `2.32 xx 10^(-4)`
C. `2.32 xx 10^(-3)`
D. `1.16 xx 10^(-4)`

Answer

D

Explanation

No. of moles of `Ag^(+) = (15 xx 60 xx 1.25 xx 10^-3)/(96, 500) xx (1)/(1) = 0.016 xx 10^(-3)`
`therefore [Ag^(+)] = (1.16 xx 10^(-5))/((100)/(1000)) = 1.16 xx 10^(-4)`