A lead storage battery containing `5.0` L of 1N `H_(2)SO_(4)` solution is operated for `9.65xx10^(5)` s with a steady current of 100 mA. Assuming volume of the solution remaining constant, normality of `H_(2)SO_(4)` will

Options

A. remain unchanged
B. increases by 0.20
C. increase by unity
D. decreases by 0.40

Answer

D

Explanation

The reaction indicates that 2 moles of `H_(2)S O_(4)` corresponds to `2 xx 96500 C ` and 2 mole of `H_(2) SO_(4) = 4 ` equiv. of `H_(2) SO_(4)` .
`2 xx 96500 C` consumed 4 equiv. of `H_(2)SO_(4)` and `100 xx 10^(-3) xx 9.65 xx 10^(5)` C consumed = `(4 xx 100 xx 10^(-3) xx 9.65 xx 10^(5))/(2 xx 96500) = 2 ` equiv. `H_(2) SO_(4)`
`therefore` Decrease in normality = `(2)/(5) = 0.40`