The products obtained when chlorine gas reacts with cold and dilute aqueous `NaOH` are :

Options

A. `CIO^(-)" and "CIO_(3)^(-)`
B. `CIO_(2)^(-)" and "CIO_(3)^(-)`
C. `CI^(-)" and "CIO^(-)`
D. `CI^(-)" and "CIO_(2)^(-)`

Explanation

To determine the products obtained when chlorine gas reacts with cold and dilute aqueous sodium hydroxide, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Chlorine gas (Cl₂)
- Cold and dilute aqueous sodium hydroxide (NaOH)

### Step 2: Understand the Reaction Conditions
The conditions specified are:
- Cold temperature
- Dilute solution

These conditions are important because they influence the products formed during the reaction.

### Step 3: Write the Reaction Equation
When chlorine gas reacts with cold and dilute sodium hydroxide, the reaction can be represented as follows:

\[ \text{Cl}_2 + 2 \text{NaOH} \rightarrow \text{NaCl} + \text{NaClO} + \text{H}_2\text{O} \]

### Step 4: Identify the Products
From the reaction equation, the products formed are:
- Sodium chloride (NaCl)
- Sodium hypochlorite (NaClO)
- Water (H₂O)

### Step 5: Write the Ionic Form of the Products
In ionic form, the products can be represented as:
- Cl⁻ (from NaCl)
- ClO⁻ (from NaClO)
- H₂O (water remains as is)

### Step 6: Analyze the Options
If the options provided in the question include the ionic forms of the products, we can identify the correct answer by matching the products obtained from the reaction with the options available.

### Conclusion
The products obtained when chlorine gas reacts with cold and dilute aqueous sodium hydroxide are:
- Sodium chloride (NaCl)
- Sodium hypochlorite (NaClO)
- Water (H₂O)

Thus, the correct answer corresponds to the ionic forms of the products, which would be Cl⁻, ClO⁻, and H₂O.