Chlorine upon reaction with `NaOH` in cold yields :

Options

A. `NaCl, NaClO, H_(2)O`
B. `NaCl, NaClO_(3), H_(2)O`
C. `NaClO, NaClO_(3), H_(2)O`
D. `NaCl, H_(2)O`

Explanation

To determine the products formed when chlorine reacts with sodium hydroxide in cold conditions, we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are chlorine gas (Cl₂) and sodium hydroxide (NaOH) in a cold aqueous solution.

### Step 2: Identify the Reaction Type
Chlorine reacts with sodium hydroxide to form sodium chloride (NaCl), sodium hypochlorite (NaClO), and water (H₂O). This is a redox reaction where chlorine is reduced and sodium hydroxide acts as a base.

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction is:
\[ \text{Cl}_2 + 2 \text{NaOH} \rightarrow \text{NaCl} + \text{NaClO} + \text{H}_2\text{O} \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products of the reaction are:
1. Sodium chloride (NaCl)
2. Sodium hypochlorite (NaClO)
3. Water (H₂O)

### Step 5: Conclusion
Thus, when chlorine reacts with sodium hydroxide in cold conditions, the products formed are sodium chloride, sodium hypochlorite, and water.

### Final Answer
The products formed are NaCl, NaClO, and H₂O.

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