Blue solid which is obtained on racting equimolar amounts of two gases at 245K is

Options

A. `N_(2)O`
B. `N_(2)O_(3)`
C. `N_(2)O_(4)`
D. `N_(2)O_(5)`

Explanation

To solve the question regarding the blue solid obtained from the reaction of equimolar amounts of two gases at 245K, we can follow these steps:

### Step 1: Identify the Gases Involved
The question mentions that we are reacting two gases in equimolar amounts. The gases that are typically involved in the formation of nitrogen oxides are nitrogen (N2) and oxygen (O2). However, in this case, we are looking for specific nitrogen oxides that can form a blue solid.

**Hint:** Consider the common nitrogen oxides and their properties.

### Step 2: Consider the Possible Products
The options given are N2O, N2O3, N2O4, and N2O5. We need to determine which of these can be formed from the reaction of nitrogen and oxygen gases.

- N2O (nitrous oxide) is a gas.
- N2O3 (dinitrogen trioxide) is a solid and is known to have a blue color.
- N2O4 (dinitrogen tetroxide) is a gas at room temperature.
- N2O5 (dinitrogen pentoxide) is also a solid but is not blue.

**Hint:** Focus on the physical state and color of the products.

### Step 3: Analyze the Reaction
When nitrogen (N2) reacts with oxygen (O2) at lower temperatures, it can form various nitrogen oxides. At 245K, the formation of dinitrogen trioxide (N2O3) is favored. The reaction can be represented as follows:

\[ 2NO + NO2 \rightarrow N2O3 \]

Dinitrogen trioxide (N2O3) is known to be a blue solid.

**Hint:** Recall the conditions under which specific nitrogen oxides form.

### Step 4: Conclusion
Based on the analysis, the blue solid obtained from the reaction of equimolar amounts of nitrogen and oxygen gases at 245K is dinitrogen trioxide (N2O3).

### Final Answer
The blue solid obtained is **N2O3 (dinitrogen trioxide)**.

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