The product formed in the reaction of `SOCl_2` with white phosphorus is

Options

A. `PCI_3`
B. `SO_(2)Cl_2`
C. `SCI_3`
D. `POCl_3`

Explanation

To determine the product formed when sulfuryl chloride (SOCl₂) reacts with white phosphorus (P₄), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- White phosphorus (P₄)
- Sulfuryl chloride (SOCl₂)

### Step 2: Write the Reaction
When white phosphorus reacts with sulfuryl chloride, the reaction can be represented as:
\[ P_4 + SOCl_2 \rightarrow ? \]

### Step 3: Determine the Products
From the reaction of P₄ with SOCl₂, the products formed are:
- Phosphorus trichloride (PCl₃)
- Sulfur dioxide (SO₂)
- Disulfur dichloride (S₂Cl₂)

### Step 4: Balance the Reaction
To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation can be written as:
\[ P_4 + 4 SOCl_2 \rightarrow 4 PCl_3 + 4 SO_2 + 2 S_2Cl_2 \]

### Step 5: Identify the Main Product
Among the products formed, phosphorus trichloride (PCl₃) is the primary product of interest in this reaction.

### Conclusion
Thus, the product formed in the reaction of SOCl₂ with white phosphorus is phosphorus trichloride (PCl₃).

### Final Answer
The correct answer is **PCl₃**.

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