Potassium chlorate on heating with cone `H_2SO_4` gives

Options

A. chlorine dioxide
B. `HClO_4`
C. `KHSO_4`
D. All of thse

Explanation

To solve the problem of what potassium chlorate (KClO3) produces when heated with concentrated sulfuric acid (H2SO4), we can follow these steps:

### Step 1: Identify the Reactants
We start with potassium chlorate (KClO3) and concentrated sulfuric acid (H2SO4) as our reactants.

### Step 2: Write the Reaction
When potassium chlorate is heated with concentrated sulfuric acid, a chemical reaction occurs. The general reaction can be represented as:
\[ \text{KClO}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{KHSO}_4 + \text{HClO}_4 + \text{ClO}_2 + \text{H}_2\text{O} \]

### Step 3: Identify the Products
From the reaction, we can identify the products formed:
1. Potassium hydrogen sulfate (KHSO4)
2. Perchloric acid (HClO4)
3. Chlorine dioxide (ClO2)
4. Water (H2O)

### Step 4: Analyze the Options
Now, we need to check the given options:
- Chlorine dioxide (ClO2)
- HClO4
- KHSO4
- All of them

Since all the products formed in the reaction are listed in the options, we can conclude that the correct answer is "all of them."

### Step 5: Conclusion
Therefore, the final answer to the question is that potassium chlorate on heating with concentrated sulfuric acid gives all of the products mentioned.