In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` are possible. It is due to

Options

A. availability of vacant d orbitals in P but not in N.
B. lower electronegativity of P than N.
C. lower tendency of H-bond formation in Pthan N.
D. Occurrence of P in solid while N in gaseous state at room temperature.

Answer

A

Explanation

`""_(7)N=1s^(2)2s^(2)2p^(3), " " ""_(15)P= 1s^(2)2s^(2)2p^(6)3s^(2)3p^(3)`
In phosphorous the 3d-orbitals are available. Hence phosphorous can from pentahalitals but nitrogen can not form pentahalide due to absence of d-orbitals.