The formation of `O_(2)^(+)[PtF_(6)]^(-)` is the basis for the formation of xenon fluorides. This is because:

Options

A. `O_2` and Xe have comparable sizes.
B. Both `O_2` and Xe are gases.
C. `O_2` and Xe have comparable ionisation energies.
D. Both (a) and ( c ) .

Answer

D

Explanation

(i) The first ionization energy of xenon `(1,170 kJ mol^(-1))` is quite close to that of dioxygen `(1,180 kJ mol^(-1))`.
(ii) The molecular diameters of xenon and dioxygen are almost identical.
Based on the above similarities Barlett (who prepared `O_(2)^(+)[PtF_6]^(-)` compound) suggested that since oxygen combines with `PtF_(6)`, so xenon should also form similar compound with `PtF_(6)`.