A car stopped after travelling distance 8m due to applying brakes at the speed of 40 m/s. Find acceleration and retordation of car in that period. (`v^(2)-u^(2)=2as`)

A car travelling at a speed of 20 ms^-1 applies brackes and stops within 10s. What is the acceleration of car?

A car moving with speed v on a straight road can be stopped with in distance d on applying brakes. If same car is moving with speed 3v and brakes provide half retardation, then car will stop after travelling distance

A car moving with speed v on a straight road can be stopped with in distance d on applying brakes. If same car is moving with speed 3v and brakes provide half retardation, then car will stop after travelling distance

When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then retardation will be :

A car travelling at a speed of 10m/s stops in 4s after the application of brakes. If we assume the retardation to be constant. Find the retardation.

A car is moving in a straight line with speed 18 km h^(-1) . It is stopped in 5 s by applying the brakes. Find : (i) the speed of car in m s^(-1) , (ii) the retardation and (iii) the speed of car after 2 s of applying the brakes.

A car moving along a straight line at a speed of 72km/h stops in 5s. After the brakes are applied. Find the acceleration

A 1000 kg car is travelling at 108 km/h when the brakes are applied. If the car stops in 10 m, find the stopping force .