The frequency of a stretched uniform wire under tension is in resonance with the fundamental frequency of a closed tube. If the tension in the wire is increased by 8 N , it is in resonance with the first overtone of the closed tube. The initial tension in the wire is

Options

A. 1N
B. 4N
C. 8N
D. 16N

Answer

A

Explanation

According to problem
`1/(2L)sqrt(T/m)=v/(4L)`....(i) and `1/(2L) sqrt((T+8)/m)=(3v)/(4l)`....(ii)
Dividing equation (i) by (ii) `sqrt(T/(T+8))=1/3 impliesT=1N`