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Let [epsilon(0)] denote the dimensional ...

Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the permeability of the vacuum. If `M = mass ,L = length, T = time and I = electric current`,

A

`[epsilon_(0)]=M^(-1)L^(3)T^(2)I`

B

`[epsilon_(0)]=M^(-1)L^(-3)T^(4)I^(2)`

C

`[mu_(0)]=MLT^(-2)I^(-2)`

D

`[mu_(0)]=ML^(2)T^(-1)I`

Text Solution

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The correct Answer is:
B, C
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