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An object moves at a constant speed alon...

An object moves at a constant speed along a circular path in a horizontal `XY` plane, with the center at the origin. When the object is at `x=-2m`, its velocity is `-(4m//s)hatj`. What is the object's acceleration when it is `y=2m`

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The correct Answer is:
(a)`-(4m//s)hati;` (b) `-(8m//s^(2))hatj`
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