A bullet of mass m is fired at speed `v_0` into a wooden block of mass M. The bullet instantaneously comes to rest in the block. The block with the embedded bullet slides along a horizontal surface with a coefficient of kinetic friction `mu`.

Which one of the following expressions determines how far the block slides before it comes to rest (the magnitude of displacement s is as shown in the figure)?

Options

A. `s=(mv_0^2)/(M mug)`
B. `s=m/(m+M)(v_0^2/(mug))`
C. `s=(m/(m+M))^2 v_0^2/(2mug)`
D. `s=(m/(m+M))^2 sqrt(v_0^2/(2mug))`

Answer

C