A block whose mass m is 680g is fastened to a spring whose spring constant k is 65N/m. The block is pulled a distance x=11cm from its equilibrium position at x=0 on a frictionless surface and released from rest at t= 0.
What is the phase constant `phi` for the motion?

Explanation

To find the phase constant \( \phi \) for the motion of the block attached to the spring, we can follow these steps:

### Step 1: Understand the system
The block is attached to a spring and is displaced from its equilibrium position. When released, it will undergo simple harmonic motion (SHM). The displacement \( x \) from the equilibrium position can be described by the equation:
\[ x(t) = A \sin(\omega t + \phi) \]
where:
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