A particle undergoing simple harmonic oscillation of period T (like that in Fig. 15-1) is at `-x_(m)` at time t=0. Is it at `-x_(m)` at `+x_(m)` at 0, between `-x_(m)` and 0, or between 0 and `+x_(m)` when (a) t= 2.00T, (b) t = 3.05T, and (c ) t= 5.25T?

Explanation

To solve the problem, we need to analyze the position of a particle undergoing simple harmonic motion (SHM) at given times based on its oscillation characteristics. The particle starts at `-x_m` when `t = 0`. The period of the oscillation is `T`.

### Step-by-Step Solution:

1. **Understanding the Motion**:
- The particle is at `-x_m` at `t = 0`. In SHM, the particle moves from `-x_m` to `+x_m` and back, completing one full cycle in time `T`.
- The positions at key points in one cycle are:
- At `t = 0`: `-x_m`
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