An object undergoing simple harmonic motion takes 0.25g to travel from one point of zero velocity to the next such point. The distance between those points is 32cm. Calculate the (a) period (b) frequency and (c ) amplitude of the motion.

Explanation

To solve the problem step by step, we will break down the information given and apply the concepts of simple harmonic motion (SHM).

### Given Data:
- Time taken to travel from one point of zero velocity to the next: \( t = 0.25 \, \text{s} \)
- Distance between the two points of zero velocity: \( d = 32 \, \text{cm} = 0.32 \, \text{m} \)

### Step 1: Calculate the Period (T)
In SHM, the time taken to move from one point of zero velocity to the next (which is half of the complete cycle) is \( t \). Therefore, the time period \( T \) (which is the time for a complete cycle) is given by:
...