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A 0.0500 kg lead bullet of volume 5.00 x...

A 0.0500 kg lead bullet of volume `5.00 xx 10^(-6) m ^(3)` at `20.0^(@)C` hits a block that is made of an ideal thermal insulator and comes to rest at its center. At that time, the temperature of the bullet is `327^(@)C`. Use the following information for lead `:`
Coefficient of linear expansion `: alpha = 2.0 xx 10^(-5)// ""^(@)C`
Specific heat capacity `:` `c = 128 J // ( kg . ""^(@)C )`
Latent heat of fusion `:` `L_(1) = 23 300 J // kg`
Melting point `:` `T_("melt") = 327^(@)C`
What additional heat would be needed to melt the bullet ?

A

420J

B

837 J

C

628 J

D

1160 J

Text Solution

Verified by Experts

The correct Answer is:
D
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A 0.0500 kg lead bullet of volume 5.00 xx 10^(-6) m ^(3) at 20.0^(@)C hits a block that is made of an ideal thermal insulator and comes to rest at its center. At that time, the temperature of the bullet is 327^(@)C . Use the following information for lead : Coefficient of linear expansion : alpha = 2.0 xx 10^(-5)// ""^(@)C Specific heat capacity : c = 128 J // ( kg . ""^(@)C ) Latent heat of fusion : L_(1) = 23 300 J // kg Melting point : T_("melt") = 327^(@)C How much heat was needed to raise the bullet to its final temperature ?

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