One mole of oxygen ( Assume it to be an ideal gas ) expands at a constant temperature T of 310 K from an intital volume `V_i ` of `12 L` to a final volume `V_f` of 19 L . How much work is done by the gas during the expansion ?

Explanation

To solve the problem of calculating the work done by one mole of oxygen gas during an isothermal expansion from an initial volume \( V_i = 12 \, L \) to a final volume \( V_f = 19 \, L \) at a constant temperature \( T = 310 \, K \), we will use the formula for work done in an isothermal process for an ideal gas.

### Step-by-Step Solution:

1. **Identify the Formula for Work Done**:
The work done \( W \) by an ideal gas during an isothermal expansion can be calculated using the formula:
\[
W = nRT \ln\left(\frac{V_f}{V_i}\right)
...