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Let 1.00 Kg of liquid water at 100...

Let 1.00 Kg of liquid water at `100^@ C ` converted to steam at `100^@ C ` by boiling at standard atmospheric pressure ( which is 1.00 atm or `1.01 xx 10^5` Pa ) in the arrangement of the volume of that water changes from an initial value of `1.00 xx 10^3 m^3 ` as a liquid to `2.671 * 10^3 m^3 ` as steam
(a) How much work is done by the system during this process ?

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AI Generated Solution

To solve the problem of calculating the work done by the system during the conversion of 1.00 kg of liquid water at 100 °C to steam at 100 °C, we will use the formula for work done in a constant pressure process. The steps are as follows: ### Step-by-Step Solution: 1. **Identify the given data:** - Mass of water, \( m = 1.00 \, \text{kg} \) - Initial temperature, \( T_i = 100 \, \text{°C} \) - Final temperature, \( T_f = 100 \, \text{°C} \) ...
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