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Let 1.00 Kg of liquid water at 100...

Let 1.00 Kg of liquid water at `100^@ C ` converted to steam at `100^@ C ` by boiling at standard atmospheric pressure ( which is 1.00 atm or `1.01 xx 10^5` Pa ) volume of that water changes from an initial value of `1.00 xx 10^3 m^3 ` as a liquid to `1.671 m^3 ` as steam
How much energy is transferred as heat during the process ?

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To solve the problem of converting 1.00 kg of liquid water at 100°C to steam at 100°C, we need to calculate the energy transferred as heat during this phase change. The energy required for this process is given by the formula for latent heat. ### Step-by-Step Solution: 1. **Identify the Mass of Water**: The mass (m) of the water is given as 1.00 kg. 2. **Determine the Latent Heat of Vaporization**: ...
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