Two infinite, non-conducting sheets of charge are parallel to each other, as shown in figure. The sheet on the left has a uniform surface charge density `sigma`, and the one on the right has a uniform charge density `-sigma`. Calculate the electric field at points (a) to the left of, (b) in between, and (c) to the right of the two sheets.

Explanation

At any point the electric field `vecE _((+))` due to the positive sheet is directed away from the sheet and , from has the magnitude
`E _((+))= (sigma _((+)))/(2 epsi _(0)) = (6. 8 xx 10 ^(-6) C//m ^(2))/((2) ( 8.85 xx 10 ^(-12) C ^(2) C ^(2) //N.m^(2)))`
`=3.43 xx 10 ^(3)N//C.`
(a) Two large parallel sheets, uniformaly charged on one side. (b) The individual electric fields resulting from the two charged sheets. (c ) The net field due to both charged sheets, found by superposition.
Similarly, at any point, the electric field `vecE_((-))` due to the negative sheet is directed toward that sheet and has the magnitude
` E _((-))= (sigma _((-1)))/( 2 epsi _(0)) (4.3 xx 10 ^(-6) C//m ^(2))/((2) (8.85 xx 10 ^(-12) C ^(2) //N.m^(2)))`
`= 23.43 xx 10 ^(5) N//C.`
shows the fields set up by the sheets to the feft of the sheets (L) between them (B), and to their right (R).
The resultant fields in thtese three regions follow from the superposition principle. To the left, the field magnitude is
`E _(1)=E _((+)) - E _((-))`
` = 3. 84 xx 10 ^(5) N//C - 2. 43 xx 10 ^(5) N//C`
` = 1.4 xx 10 ^(5) N//C.`