Home
Class 12
PHYSICS
An electron is placed just in the middle...

An electron is placed just in the middle between two long fixed line charges of charge density `+lambda` each. The wires are in the xy plane (do not consider gravity)

A

The equilibeium of the electron will be unstable along x direction.

B

The equlibrium of the electron will be lneutral along y diraction.

C

The equlibrium of the electron will be stable along z direction.

D

The equlibrium of the electron will be stable along y direction.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Promotional Banner

Topper's Solved these Questions

  • GAUSS' LAW

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (LINKED COMPREHENSION)|6 Videos
  • GAUSS' LAW

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (INTEGER TYPE)|3 Videos
  • GAUSS' LAW

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (SINGLE CORRECT CHOICE TYPE)|20 Videos
  • FORCE AND MOTION-II

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Integer Type)|1 Videos
  • GEOMETRICAL OPTICS : REFLECTION

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Integer Type)|3 Videos

Similar Questions

Explore conceptually related problems

The electric field intensity due to a thin infinity long straight wire of uniform linear charge density lambda at O is-

An electric dipole of moment p is kept at a distance r form an infinte long charged wire of linear charge density lambda as shown.Find the force acting on the dipole?

A charge particle q is released at a distance R_(@) from the infinite long wire of linear charge density lambda . Then velocity will be proportional to (At distance R from the wire)

Figure shows a long wire having uniform charge density lambda as shown in figure. Calculate electric field intensity at point P.

Find the force experienced by a semicircular rod having a charge q as shown in fig. Radius of the wire is R, and the line of charge with linear charge density lambda passes through its center and is perpendicular to the plane of wire.

Find the electric flux crossing the wire frame ABCD of length l, width b, and center at a distance OP = d from an infinite line of charge with linear charge density lambda . Consider that the plane of the frame is perpendicular to the line OP

The figure below depict two situations in which two infinitely long static line charges of constant positive line charge density lambda are kept parallel to each other. In their resulting electric field, point charges q and -q are kept in equilibrium between them. The point charges are confined to move in the x direction only. If they are given a small displacement about their equilibrium positions, then the correct statement(s) is(are)

The are AB with the centre C and infinitely long wire having linear charge density lambda are lying in the same plane. The minium amount of work to be done to move a point charge q_(0) from point A to B through a circular path AB of radius a is equal to

Knowledge Check

  • The electric field intensity due to a thin infinity long straight wire of uniform linear charge density lambda at O is-

    A
    `(lambda)/(2pi epsilon_(0)R)`
    B
    `(lambda sqrt(2))/(2pi epsilon_(0)R)`
    C
    `(lambda sqrt(5))/(2pi epsilon_(0)R)`
    D
    zero
  • A charge particle q is released at a distance R_(@) from the infinite long wire of linear charge density lambda . Then velocity will be proportional to (At distance R from the wire)

    A
    `R^(3)`
    B
    `e^(R//R_(0))`
    C
    `R^(2)`
    D
    `[n((R)/(R_(0)))]^(-1//2`
  • An electron moves straight inside a charged paralle plane capacitor of uniform charge density sigma . The space between the plates is filled with uniform magnetic field of intensity B, as shown in the figure. Neglecting effect of gravity, the time of straight line motion of the electron in the capacitor is

    A
    `(epsi_(0)iB)/(sigma)`
    B
    `(sigma)/(epsi_(1) iB)`
    C
    `(epsi_(2)B)/(sigma)`
    D
    `(sigma)/(epsi_(1)B)`