[" Nueclues "x^(" A ")" emites "2 alpha,2 beta" nuclean "],[" the n/p ratio for final "]

A nucleus ._(Z)X^(A) emits 2 alpha - particles and 3 beta - particles. The ratio of total protons and neutrons in the final nucleus is :

._(n)X^(m) emitted one alpha and 2beta particles, then it will become :

A nucleus ._ZX^A emits 9 alpha- particles and 5p particle. The ratio of total protons and neutrons in the final nucleus is.

A nucleus ._ZX^A emits 9 alpha- particles and 5p particle. The ratio of total protons and neutrons in the final nucleus is.

._(92)U^(238) emits 8 alpha- particles and 6 beta- particles. The n//p ratio in the product nucleus is

._(92)U^(238) emits 8 alpha- particles and 6 beta- particles. The n//p ratio in the product nucleus is

An A.P. consists of 2n terms. If two middle terms are alpha - beta and alpha + beta , then sum of the 2n terms of the A.P. is

Let the ordinates of points P and Q on the parabola y^2 = 12x be in the ratio 1:3 and (alpha, beta) be the point of intersection of normals to parabola at P and Q , then (12^2(alpha-6)^3/(beta^2)=

Let alpha and beta the roots of x^(2) -6x -2=0 with alpha gt beta if alpha_(n) alpha^(n)- beta^(n) for n gt 1 then the value of (a_(10) -2ds)/(2a_(p)) is :