`K_(sp)` of `PbBr_(2)` is `8 xx 10^(-5)`. If the salt is `80%` dissociated in solution, calculat the solubility of salt in `gL^(-1)`.

K_(sp) of PbBr_(2) is 8 xx 10^(-5) . If the salt is 80% dissociated in solution, calculate the solubility of salt in gL^(-1) .

K_("sp") of PbBr_(2) (Molar mass =367 ) is 3.2xx10^(-5) . If the salt is 80% dissociated in solution, caculate the solubility of salt in g per litre .

K_("sp") of PbBr_(2) (Molar mass =367 ) is 3.2xx10^(-5) . If the salt is 80% dissociated in solution, caculate the solubility of salt in g per litre .

The solubility product of lead bromide is 8xx10^(-5) at 298 K. If the salt is 80% dissociated in saturated solution, calculate the solubility of the salt (in gram/litre)

The solubility product of lead bromide is 8 xx 10^(-5) . If the salt is 80% dissociated in saturated solution, find the solubility of the salt :-

At 25^(@) C, K_(sp) for PbBr_(2) is equal to 8xx10^(-5) . If the salt is 80% dissociated, What is the solubility of PbBr_(2) in mol//litre?

At 25^(@) C, K_(sp) for PbBr_(2) is equal to 8xx10^(-5) . If the salt is 80% dissociated, What is the solubility of PbBr_(2) in mol//litre?

At 25^(@) C, K_(sp) for PbBr_(2) is equal to 8xx10^(-5) . If the salt is 80% dissociated, What is the solubility of PbBr_(2) in mol//litre?

At 25^oC , K_(sp) for AB_2 salt is equal to 8xx10^-6 . If the salt is 70% dissociated, then the solubility of AB_2 in mol/litre is