The logarithm of `0.00001` to the base `0.01` is equal to a. `-5/2` b. `5/2` c. `3` d. `5`

The logarithm of 0.0625 to the base 2 is a.-4 b.-2 c.0.25 d.0.5

What is the logarithm of 0.0001 with respect to base 10 ?

Let N=10^(log2-2log(log10^(3))+log(log10^(6))^(2)) where base of the logarithm is 10. The characteristic of the logarithm of N the base 3, is equal to (a) 2 (b) 3 (c) 4 (d) 5

log_(0.01) 1000 +log_(0.1)0.0001 is equal to :

log_(0.01) 1000 +log_(0.1)0.0001 is equal to :

Find the logarithm of 1600 with respect to the base 2root(3)(5) .

Find the logarithms of (i) 1728 to the base 2sqrt(3) (ii) 0.00001 to the base 0.01

If the logarthim of a^(2) top the base b^(3) and the logarithm of b^(8) to the base a^(12) be equal find the value of each logarithm

(1/5)^0 is equal to (a)0 (b) 1/5 (c) \ 1 (d) 5