1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is (`K_(f) of H_(2)O = 1.86 K kg "mol"^(-1)`):

1.0 g of a weak monobasic acid HA in 100 g water lowers the freezing point by 0.155 K. If 0.45 g, of same acid requires 15 mL of N/5 NaOH solution for complete neutralistion then %, degree ofionization of acid is (K_f " of H"_(2)O="1.86 K kg mol"^(-1)) . a)0.2 b)0.25 c)0.4 d)0.5

1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

1.0 gram of a monobasic acid HA in 100 gram H_2O lower the freezing point by 0.155 K.0.45 gram of same acid require 15 ml of 1/5 M KOH solution for complete neutralisation.If the degree of dissociation of acid is alpha , then value of '20alpha' is : ( K_f for H_2O =1.86 K.Kg/mole)