Determine the force P required to impend the motion of the block B shown in figure. Take coefficient of friction = 0.3 for all surfaces in contact.

Find the contact force between the block and acceleration of the blocks as shown in figure.

Three blocks are connected as shown in the figure. Valculate the minimum force required to move the body with constant velocity. The coefficient of friction at all surfaces is 0.25.

Block of mass m are released from rest and they slide down the inclined surface as shown in figure. Show that the work done by the frictional forces on the blocks are same in all the cases. Also calculate the speeds with which the blocks reach point B. The coefficient of friction for all the surface is mu_k .

Block A of weight 500 N and block B of weight 700 N are connected by rope pulley system as shown. The largest weight C that can be suspended without moving block A and B is W . The coefficient of friction for all plane surfaces of contact is 0.3 . The pulleys are ideal. Find (W)/(90) .

The block of mass 'm' initially at x=0 is acted upon by a horizontal force F=a-bx as shown in the figure. The coefficient of friction between the surfaces of contact is mu . The net work done on the block is zero if the block travels a distance of ________ .

Two blocks A and B of masses 10 kg and 15 kg are placed in contact with each other rest on a rough horizontal surface as shown in the figure. The coefficient of friction between the blocks and surface is 0.2. A horizontal force of 200 N is applied to block A. The acceleration of the system is ("Take g"=10ms^(-2))

Each of the two block shown in the figure has mass m. The pulley is smooth and the coefficient of friction for all surfaces in contact is mu . A constant horizontal force P applied in two cases shown in such a way that block A start just sliding then the value of minimum force P in case-I and case-II is :

A horizontal force of 20 N is applied to a block of 10 kg resting on a rough horizontal surface. How much additional force is required to just move the block, if the coefficient of static friction between the block and the surface is 0.4 ?

Calculate the Force (F) required to cause the block of mass m_(1) = 20 kg just to slide under the block of mass m_(2) = 10 kg [ coefficient of friction mu = 0*25 for all surfaces ]

A force of 100N is applied on a block of mass 3 kg as shown in the figure-2.164. The coefficient of friction between the surface and the block is 0.25.The frictional force acting on the block is: (Take g=10m/s^(2) )