What potential difference must be applied to stop the fastest photoelectrons emitted by a nickel surface under the action of ultraviolet light of wavelength `2000Å`? The work function of nickel is 5.01 eV.

What P.D. must be applied to stop the fastest photo electron emitted by a nickel surface when illuminated by ultraviolet light of wave length 2000^(@)A . The work function of nickel is 5 eV

What P.D. must be applied to stop the fastest photo electron emitted by a nickel surface when illuminated by ultraviolet light of wave length 2000^(@)A . The work function of nickel is 5 eV

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface , having work function 5.01 eV , when ultraviolet light of 200 nm falls on it , must be

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV , when ultraviolet light of 200nm falls on it, must be:

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface , having work function 5.01 eV , when ultraviolet light of 200 nm falls on it , must be

Five volt of stopping potential is needed for the photoelectrons emitted out of a surface of work function 2.2 eV by the radiation of wavelength

Five volt of stopping potential is needed for the photoelectrons emitted out of a surface of work function 2.2 eV by the radiation of wavelength

(a) The work function for the surface of aluminium is 4.2eV. Find potential difference will be required to stop the emission of maximum kinetic energy photoelectrons emitted by light of 1800Å wavelenght? (b) Determine the wavelength of that incident light for which stopping potential will be zero? (h=6.6xx10^(-34))