If the median AD of triangle ABC divides the angle BAC in the ratio `1:2, ` then show that `(sinB)/(sinC)=1/2sec(A/3).`

If the median AD of triangle ABC divides the angle BAC in the ratio 1:2, then show that (sin B)/(sin C)=(1)/(2)sec((A)/(3))

Centroid of a triangle divides its median in the ratio of 1:2 from the vertex.

If in a triangle ABC , cosA=(sinB)/(2sinC) then the triangle ABC , is

If the angles of a triangle ABC are in the ratio 1:2:3. then the corresponding sides are in the ratio ?

In a triangle ABC, E is the mid - point of median AD. Show that ar (BED) =1/4 ar (ABC)

Length of a median of a right DeltaABC is l cm. That divides right angle in the ratio 1 : 2. What is the area of triangle?