[" If the function "f(x)=[[k_(1)(x-pi)^(2)-1,x<=pi],[|k_(2)cos x,,x>pi]" is twice differentiable,then the "],[" ordered pair "(k_(1),k_(2))" is equal to: "]

If function f(x)={(k_1(x-pi)^2-1,xlepi),(k_2cosx,xgtpi):} is twice differentiable in ordered pair (k_1,k_2) . Find this ordered pair.

If the function f defined as f(x)=(1)/(x)-(k-1)/(e^(2x)-1),x!=0, is continuous at x=0, then the ordered pair (k,f(0)) is equal to:

Let k and K be the minimum and the maximum values of the function f(x)=((1+x)^(0.6))/(1+x^(0.6)), and x in[0,1] respectively,then the ordered pair (k,K) is equal to

If f(x)={[x^(2)-2x(k+1)+2,x geq1],[x-1,x<1]}, is continuous and differentiable,then the value of k is

The value of k such that the function f(x)=|x^(2)+(k-1)|x|-k| is non differentiable at exactly five points is

If the range of function f(x) = (x + 1)/(k+x^(2)) contains the interval [-0,1] , then values of k can be equal to

If the range of function f(x) = (x + 1)/(k+x^(2)) contains the interval [-0,1] , then values of k can be equal to

If the range of function f(x) = (x + 1)/(k+x^(2)) contains the interval [-0,1] , then values of k can be equal to