`x=a(cos t + log tan t/2), y =a sin t`

Find dy/dx , if x and y are connected parametrically by the equations (without eliminating the parameter). x = a(cost + log tan (t/2)), y = a sin t .

Find dy/dx , when x = a(cos t + log |tan t/2|) andy = a sin t, 0 < t < pi/2

If x= cos t+ log tan t/2 and y = sin t, then find the value of (d^2y)/(dt^2) and (d^2y)/(dx^2) at t= (pi)/4 .

If x=a(cos t+(log tan)(1)/(2)),y=a sin t then (dy)/(dx) is equal to

If x = a { cos t + log|tan t/2|} and y = a sin t, 0 < t < pi/2 , find (d^2y)/(dx^2)

If x =a ( cos t + t sin t), y = a [sin t-t cos t] then find dy/dx .

If x=cos t+(log tan t)/(2),y=sin t, then find the value of (d^(2)y)/(dt^(2)) and (d^(2)y)/(dx^(2)) at t=(pi)/(4)

If x=cos t+(log tan t)/(2),y=sin t, then find the value of (d^(2)y)/(dt^(2)) and (d^(2)y)/(dx^(2))a=(pi)/(4)