[" प्रश्न-12."],[qquad 2x+y=7]

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

The maximum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombous is

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

If [[3,-2],[-1,2]][[x],[y]]=[[11],[-5]] then 3x+7y=

The four lines given by the equations 12 x^(2)+7 x y-12 y^(2)=0 and 12 x^(2)+7 x y-12 y^(2)-x+7 y-1=0 lie along the sides of a

The four straight lines given by the equations 12x^2 + 7xy – 12y^2 = 0 and 12x^2 + 7xy - 12y^2 - x + 7y- 1 = 0 lie along the sides of a

Draw the graphs of 2x + y = 12 , x + y = 7 , x + 2y = 10 , x = 0 and y = 0 together

Find the distance between the parallel lines 12x+5y=7 and 12x+5y+7=0

4x -5y-11z=12,. x-3y+z=1 2x + 3y-7z = 2