2u^(2)-3x+5" A' "4=0

Find the point of discontinuity of y=f(u) where f(u)=(3)/(2u^(2)+5u-3) and u=(1)/(x+2)

A quadratic equation whose roots are cosec^2theta and sec^2theta can be (1) x^2-2x+ 2 =0 (2) x^2-3x + 3 = 0 (3) x^2-3x+ 4= 0 (4) x^2-5x+5= 0

If y=1/4u^(4) " and " u=2/3x^(3)+5, " then " (dy)/(dx) is

If u and v are the roots of the equation x^2+2x-2=0 , then the value of log_2(u^2+v^2)-log_2u^2-log_2v^2 is 2 (2) -1 (3) 1 (4) 0 (5) -2

The solutions of x^(2/5)+3x^(1/5)-4=0 are

The equation 5x^(5)+3x^(4)-2x^(3)-2x^(2)+3x+5=0 is a reciprocal equation of

Solve the following equations where x in R a) (x-1)|x^(2)-4x+3|+2x^(2)+3x-5=0 b) |x^(2)+4x+3|+2x+=0 c) |x+3|(x+1)+|2x+5|=0

Solve the following equations where x in R a) (x-1)|x^(2)-4x+3|+2x^(2)+3x-5=0 b) |x^(2)+4x+3|+2x+=0 c) |x+3|(x+1)+|2x+5|=0