solution of the differential equation `xdy-ydx=sqrt(x^2+y^2 )dx` is

Let y=y(x) be the solution of the differential equation xdy-ydx =sqrt(x^2-y^2) dx, x ge 1, with y(1)=0. If the area bounded by the lin x=1, x=e^(pi), y =0 and y=y(x) is alpha e^(2pi)+beta , then the value of 10 (alpha+beta) is equal to ..........

The general solution of the differential equation xdy - ydx = y^(2)dx is

The solution of the differential equation xdy+ydx-sqrt(1-x^(2)y^(2))dx=0 is (A)sin^(-1)(xy)=C-x(B)xy=sin(x+c)(C)log(1-x^(2)y^(2))=x+c(D)y=x sin x+c

Solve the differential equation xdy - ydx = sqrt(x^2+y^2)dx

What is the solution of the differential equation xdy- ydx = xy^(2) dx ?