Find the area bounded by the curve `y=sqrtx,x=2y+3` in the first quadrant and X-axis.

Find the area bounded by the curve y= sqrt(x), x= 2 y +3 in the first quadrant and Y- axis

Area bounded by the curves : y=sqrtx, x=2y+3 in the first quadrant and x-axis is :

Find the area of the region bounded by y=sqrtx ,\ x=2y+3 in the first quadrant and x-axis.

Find the area bounded by the curve y=4x^(2),x=0,x=1 and y=4 in first quadrant.

The area bounded by the curves y=sqrt(x),2y+3=x , and x-axis in the 1st quadrant is

Area ( in square unit ) bounded by the curve y= sqrt(x) , the straight line x=2y+3 in first quadrant and x- axis is-

The area bounded by the curves y=sqrt(x),2y-x+3=0, X-axis and lying in the first quadrant is