यदि दो त्रिभुज ABC और DEF इस प्रकार है कि `(AB)/(DE)=(BC)/(EF)=(CA)/(FD)=(2)/(5)` तो `ar (Delta ABC): ar (Delta DEF)=`

In Delta ABC and Delta DEF , we have (AB)/(DE)=(BC)/(EF)=(AC)/(DF)=5/7 , then ar (Delta ABC) : ar (Delta DFR) =?

If ABC and DEF are two triangles such that (AB)/(DE)=(BC)/(EF)=(CA)/(FD)=(3)/(4), then write Area (ABC):Area(DEF)

Delta ABC=Delta DEF, Prove that (AB)/(DE)=(AB+BC+AC)/(DE+EF+DF)

ABC, (DE)/(AB)=2:3 and ar(Delta DEF)=44 sq.units then ar ( DeltaABC) is

In the given figure DE||BC and AD:DB =5:4 Find the ratio ar (Delta DEF) : ar (Delta CFB)

In the given figure DE||BC and AD:DB =5:4 Find the ratio ar (Delta DEF) : ar (Delta CFB)

In Delta ABC and Delta DEF , it is given that (AB)/(DE)=(BC)/(FD) then they will be similar when

Given two triangles ABC and DEF such that DeltaABC ~ Delta DEF . Also, ar(DeltaABC)= 25cm^(2), ar (Delta DEF)= 64cm^(2) and AB=5cm . Then length of side DE is