A small body A starts sliding down from the top of a wedge (figure) whose base is equal to `l=2.10m`. The coefficient of friction between the body and the wedge surface is `k=0.140`. At what value of the angle `alpha` will the time of sliding be the least? What will it be equal to?

A small body A starts sliding down from the top of a wedge (see fig) whose base is equal to l. The coefficient of friction between the body and wedge surface is mu= 1.0 . At what value of angle q will the time of sliding be least?

A body of mass m slides down an inclined plane making an angle of 45^(@) with the horizontal. If the coefficient of friction between the body and the plane be 0.3, the acceleration of the body is approximately equal to :

A block is at rest on an inclined plane making an angle alpha with the horizontal . As the angle alpha of the incline is increased the block starts slipping when the angle of inclination becomes theta . The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle theta to the horizontal. Then the coefficient of friction is equal to

Coefficient of friction between block of mass m and fixed wedge is mu = 0.5 . For what value of (m)/(M) frictional force between block of mass m and wedge becomes zero ?

A small body of mass m slides down from the top of a hemisphere of radius r . The surface of block and hemisphere are frictionless. The height at which the body lose contact with the surface of the sphere is