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I(3)-CHBr-CH(3)" alc.KOH "longrightarrow...

I_(3)-CHBr-CH_(3)" alc.KOH "longrightarrow A(HBr)/(" Peroxide ")rarr B(" NaI ")/(" acetont ")

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Complete the missing links CH_(3)CHBrCH_(3) overset("alc. KOH")rarr Xoverset("HBr, Peroxide")rarr Y overset(CH_(3)ONa)rarr Z

Complete the missing links CH_(3)CHBrCH_(3) overset("alc. KOH")rarr Xoverset("HBr, Peroxiden")rarr Y overset(CH_(3)Ona)rarr Z

Supply structural formulae for missing compounds. (i) H_(2)C=CH_(2)+(A) rarr ClCH_(2)-CH_(2)OH underset(413K)overset(H_(2)SO_(4))(rarr) (B) underset(Delta)overset("alc. KOH")(rarr) (C ) (ii) CH_(3)CHBrCH_(3)overset("alc. KOH")(rarr)(A)underset("Peroxide")overset(HBr)(rarr)(B)overset(CH_(3)ONa)(rarr)(C ) (iii) Me_(3)CBroverset("alc. KOH")(rarr)(A) overset(HOCl)(rarr) (B) overset(NaOH)(rarr)(C )

In the reaction CH_3 underset (Br) underset(|) (CH) CH_3 overset (alc.KOH) rarr X overset(HBr) underset (Pero x ide) rarr Y overset (NaI) underset (Acet on e)rarr Z , Z is

underset(Br) underset(|) (CH_(3)CHCH_(3))overset(alc. KOH)rarr A underset("peroxide")overset(HBr)rarr B overset(CH_(3)ON a)rarrC In the above reaction sequence, the final product is :

CH_(3)underset(Br)underset(|)(C)HCH_(3)overset("alc."//KOH)toAoverset(HBr//"peroxide")toBoverset(CH_(3)ONa)toC In the above reaction sequence, the final product is :

In the reaction , CH_(3)-underset(Br)underset(|)(CH)-CH_(3)overset(alc.KOH)(to)(A)overset(HBr)underset("Peroxide")(to)(B) overset(NaI)underset("Acetone")(to)(C) The compound (C) is :