The position coordinates of a projectile projected from ground on a certain planet (with an atmosphere) are given by `y = (4t – 2t^(2))` m and `x = (3t)` metre, where t is in second and point of projection is taken as origin. The angle of projection of projectile with vertical is -

The height y and the distance x along the horizontal plane of projectile on a certain planet (with no atmosphere on it) are given by y = (8t-5t^(2)) metre and x = 6t metre , where time t is in seconds. Find the initial velocity with which the projectile is projected.

The height y nad the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t^2) m and x = 6t m , where t is in seconds. The velocity with which the projectile is projected at t = 0 is.

The height y nad the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t^2) m and x = 6t m , where t is in seconds. The velocity with which the projectile is projected at t = 0 is.

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t-5t^(2)) meter and x = 6t meter , where t is in second. The velocity with which the projectile is projected is

The height y and the distance x along the horizontal plane of a projectile on a certain planet [with no surrounding atmosphere] are given by y=[5t-8t^2] metre and x = 12t metre where t is the time in second. The velocity with which the projectile is projected is:

The height y and the distance x along the horizontal plane of a projectile on a certain planet [with no surrounding atmosphere] are given by y=[5t-8t^2] metre and x = 12t metre where t is the time in second. The velocity with which the projectile is projected is:

The height y and the distance x along the horizontal plane of a prohectile on a certain planet (with no surrounding atmosphere) are given by y=8t- 5t^(2) meter and x=6t meter,where t is in seconds.The velocity with which the projectile is projected is (Acceleration due to gravity =9.8 m s^(-2) )

The vertical height y and horizontal distance x of a projectile on a certain planet are given by x= (3t) m, y= (4t-6t^(2)) m where t is in seconds, Find the speed of projection (in m/s).