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Factorize : 7(2x+5)+3(2x+5), (x+2...

Factorize : `7(2x+5)+3(2x+5)`, `(x+2)y+(x+2)x`, `5a(2x+3y)-2b(2x+3y)`, `8(5x+9y)^2+12(5x+9y)`

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Factorize : (1) 7(2x+5)+3(2x+5) , (2) (x+2)y+(x+2)x , (3) 5a(2x+3y)-2b(2x+3y) , (4) 8(5x+9y)^2+12(5x+9y)

Factorize :7(2x+5)+3(2x+5)(x+2)y+(x+2)x5a(2x+3y)-2b(2x+3y)8(5x+9y)^(2)+12(5x+9y)

(5x + 3y) (5x-3y) (25x ^ (2) + 9y ^ (2))

Simplify: (2x + 5y)(3x + 4y) - (7x + 3y)(2x + y)

1 + 5x + 3y = 9 2x 3y = 12 X = (x, y) - 4

If y = (5x +7)/(2x -3) then y _(2) =

If (3x -4y) : (2x -3y) = (5x -6y) : (4x -5y) , find : x : y .

Factorise 25x^(2) - 30xy + 9y^(2) . The following steps are involved in solving the above problem . Arrange them in sequential order . (A) (5x - 3y)^(2) " " [ because a^(2) - 2b + b^(2) = (a-b)^(2)] (B) (5x)^(2) - 30xy + (3y)^(2) = (5x)^(2) - 2(5x)(3y) + (3y)^(2) (C) (5x - 3y) (5x - 3y)

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))