सिद्ध कीजिए कि
(ii) `int tan^(6)x dx=(1)/(5)tan^(5)x -(1)/(3)tan^(3)x+tanx-x`

int tan(3x+5)dx

(d)/(dx) ((1)/(3)tan^(3)x-tan x+x) =

int x^3 tan^-1 x dx

We can derive different reduction formulas by using integration by parts. If int tan^(6)x dx=(1)/(5) tan^(5)x+A tan^(3)x+tanx+c , then A is equal to-

(i) int tan^3 x dx (ii) int tan^4 x dx.

int x^(3)(tan^(-1)x)dx

int (tanx sec^(2)x)/((1-tan^(2)x))dx.

int tan(x)/(2)tan(x)/(3)tan(x)/(6)dx=

int(1+tan^(2)x)/(1+tanx)dx=

int(tan^(-1)x+x+tan^(-1)((1)/(x)))dx =