An element with density `11.2 g cm^(-3)` forms a f. c. c. lattice with edge length of `4xx10^(-8)` cm. Calculate the atomic mass of the element. (Given : `N_(A)= 6.022xx10^(23) mol^(-1)`

Explanation

Given, Density, `d = 11.2 g cm ^(-3)`, Edge length
`a = 4xx 10^(-8) cm,` Avogafro number,
`NA = 6.022xx10^(23)`
Number of atoms present per unit cell, Z (fcc) = 4
We know for a crystal system = `(ZxxM)/(a^(3) xxNA)`
`rArr =(dxxa^(3)xxNa)/(Z) = (11.2xx64xx10^(-24) xx6.022xx10^(23))/(4) = 107.91 g`
Thus, atomic mass of the element is `107.91` g.