The momentum of a particle is `P = A + Bt^(2)` . Where , A and B are constant perpendicular vectors . The force acting on the particle when its acceleration is at `45^(@)` with its velocity is

The linear momentum P of a particle varies with time as follows P=a+bt^(2) Where a and b are constants. The net force acting on the particle is

The linear momentum P of a particle varies with time as follows P=a+bt^(2) Where a and b are constants. The net force acting on the particle is

If a constant force acts on a particle, its acceleration will

If a constant force acts on a particle, its acceleration will

Linear momentum of a particle given by relation p = a + b t^(2) , where a, b are constant and t is time, then force acting on particle is ………..

The displacement of a particle is s = (a+bt)^(6) , where a and b are constants. Find acceleration of the particle as a function of time.

Displacement (x) of a particle is related to time (t) as x = at + b t^(2) - c t^(3) where a,b and c are constant of the motion. The velocity of the particle when its acceleration is zero is given by: