The following table gives the number of participants in a yoga camp: `[("Age in years", 20-30, 30-40, 40-50, 50-60, 60-70),("No. of Participants", 8,40,58,90,83)]`. Find the modal age of the participants.

Find the mean for the following data. {:("Marks obtained",10-20,20-30,30-40,40-50,50-60,60-70),("Number of students",8,6,12,5,2,7):}

The following table gives the marks scored by 100 students in an entrance examination. Marks:, 0-10, 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80 No. of Students (Frequency):, 4, 10, 16, 22, 20, 18, 8, 2

The following table gives the marks scored by 100 students in an entrance examination. Marks: 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 No. of Students (Frequency): 4 10 16 22 20 18 8 2 Represent this data in the form of a histogram.

For the following data the value of Q_(1) + Q_(3) - Q_(2), is {:("Age in years" ,:,20,30,40,50,60,70,80),("No. of members" ,:,3,61,132,153,140,51,3):}

For the following data the value of Q_(1) + Q_(3) - Q_(2), is {:("Age in years" ,:,20,30,40,50,60,70,80),("No. of members" ,:,3,61,132,153,140,51,3):}

The following table gives distributionn of marks secured by some stidents : {:("Wege Rate (Rs.)",10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Number of Students"," "42," "38," "120," "84," "48," "36," "31):} Calculate the median marks secured by the students.

Find the mean deviation from the mean of the following data: Classes:, 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80 frequency, 2, 3, 8, 14, 8, 3, 2

Find the mean deviation from the mean of the following data: Classes:, 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80 frequency, 2, 3, 8, 14, 8, 3, 2

The modal class for the following frequency distribution, is {:("Marks:", 0-10,10-20,20-40,40-50,50-60,60-70,70-90,90-100),("No. of students:",4,6,14,16,14,8,16,5):}