Home
Class 11
PHYSICS
The equation of motion of a particle sta...

The equation of motion of a particle started at `t=0` is given by `x=5sin(20t+pi//3)` where x is in centimeter and t in second. When does particle
(a) first come to rest
(b) first have zero acceleration
(c) first have maximum speed?

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of motion of a particle started at t=0 is given by x=5sin(20t+pi/3) , where x is in centimetre and t in second. When does the particle a. first come rest b. first have zero acceleration c. first have maximum speed?

The equation of motion of a particle started at t=0 is given by x=5sin(20t+pi/3) , where x is in centimetre and t in second. When does the particle a. first come rest b. first have zero acceleration c. first have maximum speed?

The equation of motion of a particle started at t=0 is given by x=5sin(20t+pi/3) , where x is in centimetre and t in second. When does the particle a. first come rest b. first have zero acceleration c. first have maximum speed?

The equation of motion of a particle started at t=0 is given by x=5sn(20t+pi/3) , where x is in centimetre and t in second. When does the particle a. first come rest b. first have zero acceleration c. first have maximum speed?

The equation of motion of a particle starting at t=0 is given by x=5sin(20t+π/3) , where x is in centimeter and t is in second. When does the particle come to rest for the second time?

The equation of motion of a particle starting at t=0 is given by x=5sin(20t+π/3) , where x is in centimeter and t is in second. When does the particle come to rest for the second time?

The equation of motion for an oscillating particle is given by x = 3 sin 4pi t + 4 cos pi t where x is in mm and t is in second. The particle