[tan A=(1-cos B)/(sin B)rArr tan2A-tan B=],[[" b) "0," 2) "1," 3) "1/2," 4) "114]]

If tan A=(1-cos B)/(sin B), then tan2A=tan B

cos (AB) -3cos (A + B) rArr tan A tan B =

If tan A=(1-cos B)/(sin B) , then tan3A is equal to

If tan A = (1-cos B)//sinB , then tan 2A = tan B.

If tan A = (1-cos B)//sinB , then tan 2A = tan B.

If tan A= (1- cos B)/(sin B), then tan 2A is equal to

If tan A= (1- cos B)/(sin B), then tan 2A is equal to

44.If tan A=(1-cos B)/(sin B), find tan2A in terms of tan B

If tan A = (1 - cos B)/(sin B), then what is (2 tan A )/( 1 - tan ^(2) A ) equal to ?

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , x= Tan""(5 pi)/(28)+2Tan""(pi)/(7) Then x