" 12."(x+1)/(x^(2)+4x+5)

If (x^(2)-5x+12)/(x^(2)-4x+5)>3, then the complete set of values of x

(x^(2)-7x+12)/(2x^(2)-4x+5)>0

(x^(2)-7x+12)/(2x^(2)+4x+5)>0

If x ne -1,2 and 5, then the simplified value of {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) is equal to : यदि x ne -1,2 और 5 है, तो {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) का सरलीकृत मान क्या होगा ?

The roots of 2x^(5) + x^(4) - 12x^(3) - 12x^(2) + x + 2 = 0 are

Solve (x^2-7x+12)/(2x^2-4x+5)>0

One root of the equation (12x -1)(6x -1)(4x-1)(3x-1)=5 is

Evaluate: (i) int1/(4x^2+12 x+5)\ dx (ii) int1/(x^2-10 x+34)\ dx

Evaluate: (i) int1/(4x^2+12 x+5)\ dx (ii) int1/(x^2-10 x+34)\ dx

Evaluate: (i) int1/(4x^2+12 x+5)\ dx (ii) int1/(x^2-10 x+34)\ dx