" fit) "log(log x)

int (1)/( x (log x) log (log x) ) dx is equal to a) log (log x) + C b) log | log (x log x) + C c) log | log | log (log x) || + C d) log | log (log x) | + C

Evaluate int [ " log" (log x) + (1)/((log x )^(2)) ] dx

Evaluate: int(log(log x)+(1)/((log x)^(2)))dx

Evaluate : int [ log (log x) +(1)/((log x)^(2)) ] dx

(1)/(x log x log (log x ))

Find the derivative of the w.r.t.x log [(sin (log x ) + x log x log (log x)]

State, true or false : (i) log 1 xx log 1000 = 0 (ii) (log x)/(log y) = log x - log y (iii) If (log 25)/(log 5) = log x , then x = 2 (iv) log x xx log y = log x + log y

The value of int(1)/(x+x log x)dx is 1+log x(b)x+log x(c)x log(1+log x)(d)log(1+log x)

simplify: log(log x^(4))-log(log x)